Skip to main content
Ch. 3 - Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.6.4

Derivative Calculations


In Exercises 1–8, given y = f(u) and u = g(x), find dy/dx = f'(g(x)) g'(x).


y = cos u, u = −x/3

Guida verificata passo dopo passo
1
First, identify the functions involved: y = cos(u) and u = -x/3. We need to find dy/dx using the chain rule.
The chain rule states that dy/dx = f'(u) * g'(x), where f(u) = cos(u) and u = g(x) = -x/3.
Calculate f'(u). Since y = cos(u), the derivative f'(u) with respect to u is -sin(u).
Next, calculate g'(x). Since u = -x/3, the derivative g'(x) with respect to x is -1/3.
Combine the derivatives using the chain rule: dy/dx = f'(u) * g'(x) = (-sin(u)) * (-1/3). Substitute u = -x/3 into the expression to get dy/dx = (1/3)sin(-x/3).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Chain Rule

The chain rule is a fundamental differentiation technique used when dealing with composite functions. It states that if you have a function y = f(u) and u = g(x), then the derivative dy/dx is found by multiplying the derivative of the outer function f'(u) by the derivative of the inner function g'(x). This allows us to differentiate complex functions by breaking them down into simpler parts.
Video consigliato:
05:02
Intro to the Chain Rule

Derivative of Trigonometric Functions

Understanding the derivatives of trigonometric functions is crucial for solving calculus problems involving these functions. For example, the derivative of cos(u) with respect to u is -sin(u). This knowledge is essential when applying the chain rule to differentiate composite functions involving trigonometric expressions.
Video consigliato:
Percorso guidato
6:04
Introduction to Trigonometric Functions

Differentiation of Linear Functions

Differentiating linear functions is straightforward, as the derivative of a linear function ax + b is simply the constant a. In the given problem, u = -x/3 is a linear function, and its derivative with respect to x is -1/3. This derivative is used in conjunction with the chain rule to find dy/dx for the composite function y = cos(u).
Video consigliato: