Ch. 3 - Derivatives

Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo

Hass 15th Edition

Ch. 3 - Derivatives

Problema 3.6.77

Capitolo 3, Problema 3.6.77

Find ds/dt when θ = 3π/2 if s = cosθ and dθ/dt = 5.

Guida verificata passo dopo passo

Identify the given function: s = cos(θ). We need to find ds/dt, the rate of change of s with respect to time.

Use the chain rule for differentiation, which states that ds/dt = (ds/dθ) * (dθ/dt).

Differentiate s = cos(θ) with respect to θ to find ds/dθ. The derivative of cos(θ) is -sin(θ), so ds/dθ = -sin(θ).

Substitute the given value of dθ/dt = 5 into the chain rule expression: ds/dt = -sin(θ) * 5.

Evaluate -sin(θ) at θ = 3π/2. Since sin(3π/2) = -1, substitute this value into the expression to find ds/dt.

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Chain Rule

The chain rule is a fundamental concept in calculus used to differentiate composite functions. It states that if a variable y depends on u, which in turn depends on x, then the derivative of y with respect to x is the product of the derivative of y with respect to u and the derivative of u with respect to x. In this problem, it helps find ds/dt by relating ds/dθ and dθ/dt.

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05:02

Intro to the Chain Rule

Trigonometric Derivatives

Understanding the derivatives of trigonometric functions is crucial for solving calculus problems involving these functions. The derivative of cos(θ) with respect to θ is -sin(θ). This knowledge is essential for finding ds/dθ when s = cos(θ), which is a step in applying the chain rule to find ds/dt.

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06:35

Derivatives of Other Inverse Trigonometric Functions

Evaluating Trigonometric Functions

Evaluating trigonometric functions at specific angles is necessary for solving problems involving these functions. At θ = 3π/2, the value of sin(θ) is -1. This evaluation is crucial for determining the value of ds/dθ at the given angle, which is then used to find ds/dt using the chain rule.

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Percorso guidato

6:04

Introduction to Trigonometric Functions

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