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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.1.29

Absolute Extrema on Finite Closed Intervals


In Exercises 21–36, find the absolute maximum and minimum values of each function on the given interval. Then graph the function. Identify the points on the graph where the absolute extrema occur, and include their coordinates.


g(x) = √(4 − x²), −2 ≤ x ≤ 1

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First, understand that the function g(x) = √(4 − x²) is defined for the interval −2 ≤ x ≤ 1. This is because the expression under the square root, 4 − x², must be non-negative.
Next, identify the critical points of the function within the interval. To do this, find the derivative of g(x) with respect to x. The derivative is g'(x) = -x / √(4 − x²). Set g'(x) = 0 to find critical points, which gives x = 0.
Evaluate the function g(x) at the critical point and at the endpoints of the interval. Calculate g(−2), g(0), and g(1) to determine the function values at these points.
Compare the values obtained in the previous step to identify the absolute maximum and minimum values of the function on the interval. The largest value is the absolute maximum, and the smallest value is the absolute minimum.
Finally, graph the function g(x) = √(4 − x²) over the interval −2 ≤ x ≤ 1. Mark the points where the absolute extrema occur on the graph, and label these points with their coordinates.

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Absolute Extrema

Absolute extrema refer to the highest and lowest values a function attains on a given interval. To find these, evaluate the function at critical points and endpoints of the interval. The largest value is the absolute maximum, and the smallest is the absolute minimum.
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Finding Extrema Graphically

Critical Points

Critical points occur where the derivative of a function is zero or undefined. These points are potential locations for local extrema. For the function g(x) = √(4 − x²), find the derivative, set it to zero, and solve for x to identify critical points within the interval.
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Critical Points

Graphing Functions

Graphing a function involves plotting its values over a specified interval to visually identify features like extrema. For g(x) = √(4 − x²), plot points within the interval [-2, 1] and mark the coordinates of the absolute maximum and minimum to illustrate where these extrema occur.
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Graph of Sine and Cosine Function
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Business and Economics

62. Production level Suppose that c(x)=x^3-20x^2 + 20,000x is the cost of manufacturing x items. Find a production level that will minimize the average cost of making x items.

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Checking the Mean Value Theorem


Which of the functions in Exercises 7–12 satisfy the hypotheses of the Mean Value Theorem on the given interval, and which do not? Give reasons for your answers.


f(x) = {x² − x, −2 ≤ x ≤−1

2x² − 3x − 3, −1 < x ≤ 0

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56. Airplane landing path An airplane is flying at altitude H when it begins its descent to an airport runway that is at horizontal ground distance L from the airplane, as shown in the accompanying figure. Assume that the landing path of the airplane is the graph of a cubic polynomial function y = ax^3+bx^2+cx+d, where y(-L)= H and y(0)=0.

a. What is dy/dx at x = 0?

b. What is dy/dx at x = -L?

c. Use the values for dy/dx at x = 0 and x =- L together with y(0) = 0 and y(-L) = H to show that y(x)=H[2(x/L)^3+3(x/L)^2]

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The 8-ft wall shown here stands 27 ft from the building. Find the length of the shortest straight beam that will reach to the side of the building from the ground outside the wall.

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Checking Antiderivative Formulas


Verify the formulas in Exercises 57–62 by differentiation.


∫csc²((x − 1)/3)dx = −3cot((x − 1)/3) + C

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Finding Indefinite Integrals


In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.


∫2x(1 − x⁻³) dx

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