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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.7.7a

Finding Antiderivatives
In Exercises 1–16, find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation.
(3/2)√x

Guida verificata passo dopo passo
1
Rewrite the given function in a form that is easier to integrate. Recall that \(\sqrt{x} = x^{1/2}\). So, the function becomes \(\frac{3}{2} x^{1/2}\).
Use the power rule for integration, which states that for any real number \(n \neq -1\), the antiderivative of \(x^n\) is \(\frac{x^{n+1}}{n+1} + C\), where \(C\) is the constant of integration.
Apply the power rule to \(\frac{3}{2} x^{1/2}\). Increase the exponent by 1: \(\frac{1}{2} + 1 = \frac{3}{2}\). Then divide by the new exponent: \(\frac{3}{2} \cdot \frac{x^{3/2}}{3/2}\).
Simplify the expression by multiplying \(\frac{3}{2}\) by the reciprocal of \(\frac{3}{2}\), which will simplify the coefficient.
Add the constant of integration \(C\) to the antiderivative. To check your answer, differentiate your result and verify that you get back the original function \(\frac{3}{2} x^{1/2}\).

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Antiderivative (Indefinite Integral)

An antiderivative of a function is another function whose derivative equals the original function. It represents the reverse process of differentiation and is often expressed using the integral symbol without limits. Finding antiderivatives helps solve problems involving accumulation and area.
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Introduction to Indefinite Integrals

Power Rule for Integration

The power rule for integration states that the integral of x^n (where n ≠ -1) is (x^(n+1)) / (n+1) plus a constant. This rule is essential for integrating polynomial and root functions by rewriting roots as fractional exponents and applying the formula.
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Verification by Differentiation

After finding an antiderivative, differentiating it should return the original function. This verification step ensures the correctness of the antiderivative and reinforces understanding of the relationship between differentiation and integration.
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Finding Differentials