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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.7.39

Finding Indefinite Integrals


In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.


∫(−3csc²x)dx

Guida verificata passo dopo passo
1
Recognize that the integral is of the form \(\int -3 \csc^{2}x \, dx\), where \(-3\) is a constant multiplier and \(\csc^{2}x\) is a standard trigonometric function whose integral is known.
Recall the basic integral formula: \(\int \csc^{2}x \, dx = -\cot x + C\), where \(C\) is the constant of integration.
Use the constant multiple rule for integrals, which allows you to factor out constants: \(\int -3 \csc^{2}x \, dx = -3 \int \csc^{2}x \, dx\).
Substitute the known integral result into the expression: \(-3 \int \csc^{2}x \, dx = -3 (-\cot x + C) = 3 \cot x + C'\), where \(C'\) is a new constant of integration.
Verify your result by differentiating \(3 \cot x + C'\) and confirming that it equals the original integrand \(-3 \csc^{2}x\).

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Indefinite Integral

An indefinite integral represents the most general antiderivative of a function, expressed with a constant of integration (C). It reverses differentiation and includes all possible functions whose derivative matches the integrand.
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Integration of Trigonometric Functions

Integrating trigonometric functions like csc²x involves knowing standard integral formulas, such as ∫csc²x dx = -cot x + C. Recognizing these forms simplifies finding antiderivatives.
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Verification by Differentiation

After finding an indefinite integral, differentiating the result should return the original integrand. This step confirms the correctness of the antiderivative and helps identify any errors.
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