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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.8.1.f

1. Which of the following functions grow faster than e^x as x→∞? Which grow at the same rate as e^x? Which grow slower?
f. (e^x)/2

Guida verificata passo dopo passo
1
Recall that the function \(e^x\) is an exponential function with base \(e\), and its growth rate as \(x \to \infty\) is very fast compared to polynomial or logarithmic functions.
Analyze the given function \(f(x) = \frac{e^x}{2}\). This can be rewritten as \(f(x) = \frac{1}{2} e^x\).
Since \(f(x)\) is just \(e^x\) multiplied by a constant factor \(\frac{1}{2}\), the growth rate of \(f(x)\) as \(x \to \infty\) is the same as that of \(e^x\).
In general, multiplying an exponential function by a positive constant does not change its growth rate classification; it only scales the function vertically.
Therefore, \(f(x) = \frac{e^x}{2}\) grows at the same rate as \(e^x\) as \(x \to \infty\).

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