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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.8.4a

4. Which of the following functions grow faster than x² as x→∞? Which grow at the same rate as x²? Which grow slower?
a. x² + √x

Guida verificata passo dopo passo
1
Identify the dominant term in the function as \( x \to \infty \). For the function \( f(x) = x^{2} + \sqrt{x} \), the terms are \( x^{2} \) and \( \sqrt{x} = x^{1/2} \).
Compare the growth rates of each term to \( x^{2} \). Since \( x^{2} \) grows faster than \( x^{1/2} \), the \( x^{2} \) term dominates the behavior of the function for large \( x \).
Determine if the function grows faster, slower, or at the same rate as \( x^{2} \) by considering the limit \( \lim_{x \to \infty} \frac{f(x)}{x^{2}} = \lim_{x \to \infty} \frac{x^{2} + \sqrt{x}}{x^{2}} \).
Simplify the limit expression to \( \lim_{x \to \infty} \left(1 + \frac{\sqrt{x}}{x^{2}}\right) = \lim_{x \to \infty} \left(1 + x^{-3/2}\right) \).
Evaluate the limit: since \( x^{-3/2} \to 0 \) as \( x \to \infty \), the limit equals 1, indicating that \( f(x) \) grows at the same rate as \( x^{2} \).

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