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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.8.5c

5. Which of the following functions grow faster than ln(x) as x→∞? Which grow at the same rate as ln(x)? Which grow slower?
c. ln(√x)

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1
Recall that the growth rate of functions as \(x \to \infty\) can be compared by analyzing their dominant terms or by using limits of their ratios.
Rewrite the given function \(\ln(\sqrt{x})\) using logarithm properties: \(\ln(\sqrt{x}) = \ln(x^{1/2}) = \frac{1}{2} \ln(x)\).
Compare \(\ln(\sqrt{x})\) to \(\ln(x)\) by considering the ratio \(\frac{\ln(\sqrt{x})}{\ln(x)} = \frac{\frac{1}{2} \ln(x)}{\ln(x)} = \frac{1}{2}\).
Since the ratio approaches a positive constant (\(\frac{1}{2}\)), \(\ln(\sqrt{x})\) grows at the same rate as \(\ln(x)\), but scaled by a constant factor.
Therefore, \(\ln(\sqrt{x})\) neither grows faster nor slower than \(\ln(x)\) in terms of growth rate classification; they grow at the same rate.

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