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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.6.67

Evaluate the integrals in Exercises 53–76.
67. ∫dx/(2+(x-1)²)

Guida verificata passo dopo passo
1
Recognize that the integral is of the form \(\int \frac{dx}{a^2 + (x - b)^2}\), which is a standard integral related to the arctangent function.
Rewrite the integral to clearly identify \(a\) and \(b\): here, \(a^2 = 2\) so \(a = \sqrt{2}\), and \(b = 1\).
Recall the formula for the integral: \(\int \frac{dx}{a^2 + (x - b)^2} = \frac{1}{a} \arctan\left( \frac{x - b}{a} \right) + C\).
Apply the formula by substituting \(a = \sqrt{2}\) and \(b = 1\) into the expression to write the antiderivative.
Include the constant of integration \(C\) to complete the indefinite integral.

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