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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.6.21

In Exercises 21–48, find the derivative of y with respect to the appropriate variable.
21. y=arccos(x²)

Guida verificata passo dopo passo
1
Identify the function given: \(y = \arccos(x^{2})\). We want to find \(\frac{dy}{dx}\), the derivative of \(y\) with respect to \(x\).
Recall the derivative formula for the inverse cosine function: \(\frac{d}{dx}[\arccos(u)] = -\frac{1}{\sqrt{1 - u^{2}}} \cdot \frac{du}{dx}\), where \(u\) is a function of \(x\).
In this problem, set \(u = x^{2}\). Then compute \(\frac{du}{dx} = 2x\).
Substitute \(u = x^{2}\) and \(\frac{du}{dx} = 2x\) into the derivative formula to get: \(\frac{dy}{dx} = -\frac{1}{\sqrt{1 - (x^{2})^{2}}} \cdot 2x\).
Simplify the expression inside the square root: \((x^{2})^{2} = x^{4}\), so the derivative becomes \(\frac{dy}{dx} = -\frac{2x}{\sqrt{1 - x^{4}}}\).

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