Domanda del libro di testo
In Exercises 1–24, find the derivative of y with respect to the appropriate variable.
5. y = ln(sin²θ)
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Ch. 7 - Transcendental Functions
Hass15th EditionThomas' CalculusISBN: 9780137616077
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TOC.tableOfContents
- Ch. 1 - Functions155
- Ch. 2 - Limits and Continuity240
- Ch. 3 - Derivatives337
- Ch. 4 - Applications of Derivatives293
- Ch. 5 - Integrals41
- Ch. 6 - Applications of Definite Integrals25
- Ch. 7 - Transcendental Functions490
- Ch. 8 - Techniques of Integration399
- Ch. 9 - First-Order Differential Equations66
- Ch. 10 - Infinite Sequences and Series132
- Ch. 11 - Parametric Equations and Polar Coordinates58
Capitolo 7, Problema 7.P.13
In Exercises 1–24, find the derivative of y with respect to the appropriate variable.
13. y = (x+2)^(x+2)
Guida verificata passo dopo passo1
Recognize that the function is of the form \(y = f(x)^{g(x)}\), where both the base and the exponent depend on \(x\). This suggests using logarithmic differentiation.
Take the natural logarithm of both sides: \(\ln y = \ln \left( (x+2)^{x+2} \right)\).
Use the logarithm power rule to simplify the right side: \(\ln y = (x+2) \cdot \ln (x+2)\).
Differentiate both sides with respect to \(x\). For the left side, use implicit differentiation: \(\frac{1}{y} \frac{dy}{dx}\). For the right side, apply the product rule to \((x+2) \cdot \ln (x+2)\).
After differentiating, solve for \(\frac{dy}{dx}\) by multiplying both sides by \(y\), and then substitute back \(y = (x+2)^{x+2}\) to express the derivative in terms of \(x\).
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Implicit Differentiation and Logarithmic Differentiation
When a function has a variable in both the base and the exponent, such as y = (x+2)^(x+2), logarithmic differentiation is used. Taking the natural logarithm of both sides simplifies the expression, allowing differentiation of the exponent and base separately.
Video consigliato:
06:30
Logarithmic Differentiation
Derivative of Exponential Functions with Variable Exponents
For functions where the exponent is a variable, the derivative involves applying the chain rule and product rule after rewriting the function using logarithms. This approach helps handle the complexity of differentiating expressions like a(x)^{b(x)}.
Video consigliato:
04:50Derivatives of General Exponential Functions
Chain Rule and Product Rule
The chain rule is used to differentiate composite functions, while the product rule applies when differentiating products of functions. Both are essential here because the function involves a product of terms after logarithmic transformation.
Video consigliato:
05:18The Product Rule
Pratica correlata
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In Exercises 25–30, use logarithmic differentiation to find the derivative of y with respect to the appropriate variable.
29. y = (sin θ)^√θ
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