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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 7.7.21

In Exercises 13–24, find the derivative of y with respect to the appropriate variable.
21. y = ln(cosh v) - 1/2 tanh²v

Guida verificata passo dopo passo
1
Identify the function to differentiate: \(y = \ln(\cosh v) - \frac{1}{2} \tanh^{2} v\).
Recall the derivative formulas needed: the derivative of \(\ln(u)\) is \(\frac{1}{u} \frac{du}{dv}\), and the derivative of \(\tanh v\) is \(\operatorname{sech}^2 v\).
Differentiate the first term: \(\frac{d}{dv} \ln(\cosh v) = \frac{1}{\cosh v} \cdot \sinh v\) because \(\frac{d}{dv} \cosh v = \sinh v\).
Differentiate the second term using the chain rule: \(\frac{d}{dv} \left( \frac{1}{2} \tanh^{2} v \right) = \frac{1}{2} \cdot 2 \tanh v \cdot \operatorname{sech}^2 v\).
Combine the derivatives from both terms carefully, remembering to subtract the derivative of the second term from the first to find \(\frac{dy}{dv}\).

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Derivative of Hyperbolic Functions

Hyperbolic functions such as sinh, cosh, and tanh have derivatives similar to trigonometric functions but with distinct signs. For example, the derivative of cosh(v) is sinh(v), and the derivative of tanh(v) is sech²(v). Understanding these derivatives is essential for differentiating expressions involving hyperbolic functions.
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