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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.1.45

Area: Find the area of the region bounded above by y = 2 cos x and below by y = sec x, −π/4 ≤ x ≤ π/4.

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First, identify the curves that bound the region: the upper curve is given by \(y = 2 \cos x\) and the lower curve by \(y = \sec x\) over the interval \(-\frac{\pi}{4} \leq x \leq \frac{\pi}{4}\).
Next, set up the integral for the area between the two curves. The area \(A\) is given by the integral of the difference between the upper and lower functions over the given interval: \(A = \int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \left( 2 \cos x - \sec x \right) \, dx\).
Before integrating, verify that \(2 \cos x\) is indeed greater than \(\sec x\) on the interval \([-\frac{\pi}{4}, \frac{\pi}{4}]\) to ensure the correct order of subtraction for the area calculation.
Proceed to integrate each term separately: \(\int 2 \cos x \, dx\) and \(\int \sec x \, dx\). Recall that the integral of \(\cos x\) is \(\sin x\), and the integral of \(\sec x\) is \(\ln |\sec x + \tan x|\).
Finally, evaluate the definite integral by substituting the limits \(x = \frac{\pi}{4}\) and \(x = -\frac{\pi}{4}\) into the antiderivative expression, and subtract the results to find the area.

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The problem involves trigonometric functions y = 2 cos x and y = sec x. Knowing their behavior, values, and relative positions on the interval helps determine which function is above or below, essential for setting up the integral correctly.
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The interval −π/4 ≤ x ≤ π/4 restricts the domain for integration. It's important to verify that both functions are defined and continuous on this interval to ensure the integral is valid and the area calculation is accurate.
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