Domanda del libro di testo
The integrals in Exercises 1–44 are in no particular order. Evaluate each integral using any algebraic method, trigonometric identity, or substitution you think is appropriate.
∫ dx / (x - √x)
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Ch. 8 - Techniques of Integration
Hass15th EditionThomas' CalculusISBN: 9780137616077
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TOC.tableOfContents
- Ch. 1 - Functions155
- Ch. 2 - Limits and Continuity240
- Ch. 3 - Derivatives337
- Ch. 4 - Applications of Derivatives293
- Ch. 5 - Integrals41
- Ch. 6 - Applications of Definite Integrals25
- Ch. 7 - Transcendental Functions490
- Ch. 8 - Techniques of Integration399
- Ch. 9 - First-Order Differential Equations66
- Ch. 10 - Infinite Sequences and Series132
- Ch. 11 - Parametric Equations and Polar Coordinates58
Capitolo 8, Problema 8.8.40
In Exercises 35–68, use integration, the Direct Comparison Test, or the Limit Comparison Test to test the integrals for convergence. If more than one method applies, use whatever method you prefer.
∫ from 0 to π/2 of (cot θ dθ)
Guida verificata passo dopo passo1
Identify the integral to be tested for convergence: \(\int_0^{\frac{\pi}{2}} \cot \theta \, d\theta\).
Recall that \(\cot \theta = \frac{\cos \theta}{\sin \theta}\), and note that the integrand has potential issues at the endpoints \(\theta = 0\) and \(\theta = \frac{\pi}{2}\) because \(\sin \theta\) approaches zero there.
Split the integral into two improper integrals to analyze the behavior near the problematic points: \(\int_0^{\frac{\pi}{2}} \cot \theta \, d\theta = \int_0^a \cot \theta \, d\theta + \int_a^{\frac{\pi}{2}} \cot \theta \, d\theta\) where \(a\) is some number between 0 and \(\frac{\pi}{2}\).
Use a comparison test by comparing \(\cot \theta\) near \(0\) to a simpler function that behaves like \(\frac{1}{\theta}\), since \(\sin \theta \approx \theta\) near zero, so \(\cot \theta \approx \frac{1}{\theta}\). Similarly, analyze the behavior near \(\frac{\pi}{2}\).
Determine whether the integral converges or diverges by evaluating the limits of the integral near the problematic points or by applying the Direct or Limit Comparison Test with the simpler functions identified.
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Improper Integrals
Improper integrals involve integrals with infinite limits or integrands that become unbounded within the interval. To determine convergence, one must analyze the behavior of the function near points of discontinuity or infinite limits by taking limits of definite integrals.
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Percorso guidato
11:11
Improper Integrals: Infinite Intervals
Direct Comparison Test
The Direct Comparison Test determines convergence by comparing the given integral to another integral with a known behavior. If the integrand is less than or equal to a convergent function, the integral converges; if it is greater than or equal to a divergent function, it diverges.
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Percorso guidato
09:25Direct Comparison Test
Limit Comparison Test
The Limit Comparison Test compares two functions by examining the limit of their ratio as the variable approaches a problematic point. If the limit is a positive finite number, both integrals either converge or diverge together, helping to determine the behavior of complex integrals.
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Percorso guidato
07:45Limit Comparison Test
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