Domanda del libro di testo
In Exercises 27–40, use a substitution to change the integral into one you can find in the table. Then evaluate the integral.
∫ (x^2 + 6x) / (x^2 + 3)^2 dx
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Ch. 8 - Techniques of Integration
Hass15th EditionThomas' CalculusISBN: 9780137616077
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TOC.tableOfContents
- Ch. 1 - Functions155
- Ch. 2 - Limits and Continuity240
- Ch. 3 - Derivatives337
- Ch. 4 - Applications of Derivatives293
- Ch. 5 - Integrals41
- Ch. 6 - Applications of Definite Integrals25
- Ch. 7 - Transcendental Functions490
- Ch. 8 - Techniques of Integration399
- Ch. 9 - First-Order Differential Equations66
- Ch. 10 - Infinite Sequences and Series132
- Ch. 11 - Parametric Equations and Polar Coordinates58
Capitolo 8, Problema 8.2.56
Evaluate the integrals in Exercises 31–56. Some integrals do not require integration by parts.
∫ (sin⁻¹ x)² / √(1 - x²) dx
Guida verificata passo dopo passo1
Recognize that the integral is \( \int \frac{(\sin^{-1} x)^2}{\sqrt{1 - x^2}} \, dx \). Notice that the denominator \( \sqrt{1 - x^2} \) is related to the derivative of \( \sin^{-1} x \).
Make the substitution \( t = \sin^{-1} x \). Then, by definition, \( x = \sin t \) and \( dx = \cos t \, dt \). Also, \( \sqrt{1 - x^2} = \sqrt{1 - \sin^2 t} = \cos t \).
Rewrite the integral in terms of \( t \): replace \( (\sin^{-1} x)^2 \) with \( t^2 \), and \( \frac{1}{\sqrt{1 - x^2}} dx \) with \( \frac{1}{\cos t} \cdot \cos t \, dt = dt \). So the integral becomes \( \int t^2 \, dt \).
Integrate \( \int t^2 \, dt \) using the power rule for integration: \( \int t^n \, dt = \frac{t^{n+1}}{n+1} + C \). Here, \( n = 2 \), so the integral is \( \frac{t^3}{3} + C \).
Finally, substitute back \( t = \sin^{-1} x \) to express the answer in terms of \( x \): the integral is \( \frac{(\sin^{-1} x)^3}{3} + C \).
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Inverse Trigonometric Functions
Inverse trigonometric functions, like sin⁻¹(x), are the inverses of the standard trig functions and return angles. Understanding their properties and derivatives is essential, especially since sin⁻¹(x) appears inside the integral and its derivative involves a square root expression.
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06:35
Derivatives of Other Inverse Trigonometric Functions
Integration by Parts
Integration by parts is a technique based on the product rule for differentiation, used to integrate products of functions. It is often applied when the integral involves a function multiplied by another function's derivative, such as (sin⁻¹ x)² combined with a function of x.
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Percorso guidato
06:18Integration by Parts for Definite Integrals
Substitution Method
The substitution method simplifies integrals by changing variables to transform the integral into a more manageable form. Recognizing when to use substitution, especially with expressions involving √(1 - x²), can simplify the integral or reduce it to a standard form.
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07:33Euler's Method
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