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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.9.18

Find the value of the constant c so that the given function is a probability density function for a random variable X over the specified interval.
f(x) = (1/x) over [c, c + 1]

Guida verificata passo dopo passo
1
Recall that for a function \(f(x)\) to be a probability density function (pdf) over an interval \([a, b]\), it must satisfy the condition: \(\int_a^b f(x) \, dx = 1\).
In this problem, the function is \(f(x) = \frac{1}{x}\) defined over the interval \([c, c+1]\). We need to find the value of \(c\) such that \(\int_c^{c+1} \frac{1}{x} \, dx = 1\).
Set up the integral: \(\int_c^{c+1} \frac{1}{x} \, dx = \left[ \ln|x| \right]_c^{c+1} = \ln(c+1) - \ln(c)\).
Use the logarithm property to combine the difference: \(\ln(c+1) - \ln(c) = \ln\left( \frac{c+1}{c} \right)\).
Set the integral equal to 1 and solve for \(c\): \(\ln\left( \frac{c+1}{c} \right) = 1\). From here, exponentiate both sides to isolate \(c\) and solve the resulting equation.

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