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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.5.12

In Exercises 9–16, express the integrand as a sum of partial fractions and evaluate the integrals.
∫ (2x + 1) / (x² - 7x + 12) dx

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First, factor the quadratic denominator \(x^{2} - 7x + 12\). Find two numbers that multiply to 12 and add to -7. This factors as \((x - 3)(x - 4)\).
Express the integrand as a sum of partial fractions: write \(\frac{2x + 1}{(x - 3)(x - 4)} = \frac{A}{x - 3} + \frac{B}{x - 4}\), where \(A\) and \(B\) are constants to be determined.
Multiply both sides of the equation by the denominator \((x - 3)(x - 4)\) to clear the fractions: \(2x + 1 = A(x - 4) + B(x - 3)\).
Expand the right side and collect like terms: \(2x + 1 = A x - 4A + B x - 3B = (A + B) x + (-4A - 3B)\). Then, equate the coefficients of \(x\) and the constant terms on both sides to form a system of equations: \(2 = A + B\) and \(1 = -4A - 3B\).
Solve the system of equations for \(A\) and \(B\). Once you find \(A\) and \(B\), rewrite the integral as \(\int \frac{A}{x - 3} dx + \int \frac{B}{x - 4} dx\) and integrate each term separately using the natural logarithm rule for integrals of the form \(\int \frac{1}{x - c} dx\).

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Partial fraction decomposition is a technique used to break down a complex rational function into simpler fractions that are easier to integrate. It involves expressing the integrand as a sum of fractions with simpler denominators, typically linear or irreducible quadratic factors.
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