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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.7.4h

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.
III. Using Simpson's Rule
b. Evaluate the integral directly and find |ES|.
∫ from -2 to 0 of (x² - 1) dx

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1
First, write down the definite integral to be evaluated: \(\int_{-2}^{0} (x^{2} - 1) \, dx\).
Recall that to evaluate the integral directly, you need to find the antiderivative (indefinite integral) of the integrand \(x^{2} - 1\). The antiderivative of \(x^{2}\) is \(\frac{x^{3}}{3}\), and the antiderivative of \(-1\) is \(-x\).
Combine these results to write the antiderivative function: \(F(x) = \frac{x^{3}}{3} - x\).
Apply the Fundamental Theorem of Calculus by evaluating \(F(x)\) at the upper limit and subtracting the value at the lower limit: calculate \(F(0) - F(-2)\).
To find the absolute error bound \(|E_{S}|\) for Simpson's Rule, recall the error formula: \(|E_{S}| \leq \frac{(b - a)^{5}}{180 n^{4}} \max_{a \leq x \leq b} |f^{(4)}(x)|\). Compute the fourth derivative of \(f(x) = x^{2} - 1\), determine its maximum absolute value on \([-2, 0]\), and substitute all values into the formula.

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Simpson's Rule

Simpson's Rule is a numerical method for approximating definite integrals by dividing the interval into an even number of subintervals and fitting parabolas through the function values. It generally provides more accurate results than the Midpoint or Trapezoidal Rules for smooth functions.
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Exact Evaluation of Definite Integrals

Exact evaluation involves finding the antiderivative of the integrand and applying the Fundamental Theorem of Calculus to compute the integral's exact value. This provides a benchmark to compare numerical approximations and calculate errors.
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Definition of the Definite Integral

Error Bound for Simpson's Rule (|ES|)

The error bound |ES| estimates the maximum possible difference between the exact integral and the Simpson's Rule approximation. It depends on the fourth derivative of the function and the width of the subintervals, helping assess the accuracy of the numerical method.
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Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

b. Evaluate the integral directly and find |ES|.

∫ from 0 to π of sin(t) dt

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Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

b. Evaluate the integral directly and find |ES|.

∫ from 1 to 2 of 1 / s² ds

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Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

a. Estimate the integral with n = 4 steps and find an upper bound for |ES|.

∫ from -2 to 0 of (x² - 1) dx

22
views
Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

b. Evaluate the integral directly and find |ES|.

∫ from 1 to 3 of (2x - 1) dx

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views
Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

a. Estimate the integral with n = 4 steps and find an upper bound for |ES|.

∫ from 1 to 2 of 1 / s² ds

13
views
Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

a. Estimate the integral with n = 4 steps and find an upper bound for |ES|.

∫ from 0 to 2 of (t³ + t) dt

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