Skip to main content
Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoHass 15th EditionCh. 8 - Techniques of IntegrationProblema 8.7.2h
Capitolo 8, Problema 8.7.2h

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.
III. Using Simpson's Rule
b. Evaluate the integral directly and find |ES|.
∫ from 1 to 3 of (2x - 1) dx

Guida verificata passo dopo passo
1
First, write down the integral to be evaluated directly: \(\int_{1}^{3} (2x - 1) \, dx\).
Recall the antiderivative of the integrand. For the function \(f(x) = 2x - 1\), find \(F(x)\) such that \(F'(x) = 2x - 1\).
Compute the antiderivative: \(F(x) = x^{2} - x + C\), where \(C\) is the constant of integration.
Evaluate the definite integral using the Fundamental Theorem of Calculus: calculate \(F(3) - F(1)\).
To find the Simpson's Rule error bound \(|E_{S}|\), use the formula \(|E_{S}| \leq \frac{(b - a)^{5}}{180 n^{4}} \max_{a \leq x \leq b} |f^{(4)}(x)|\). Since the integrand is a polynomial of degree 1, determine \(f^{(4)}(x)\) and use it to find \(|E_{S}|\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Simpson's Rule

Simpson's Rule is a numerical method for approximating definite integrals by dividing the interval into an even number of subintervals and fitting parabolas through the function values. It generally provides more accurate results than the Midpoint or Trapezoidal Rules for smooth functions.
Video consigliato:
5:50
Power Rules

Exact Evaluation of Definite Integrals

Exact evaluation involves finding the antiderivative of the integrand and applying the Fundamental Theorem of Calculus to compute the integral's exact value. This provides a benchmark to compare against numerical approximations.
Video consigliato:
Percorso guidato
05:43
Definition of the Definite Integral

Error Bound for Simpson's Rule (|ES|)

The error bound |ES| estimates the maximum possible difference between the exact integral and the Simpson's Rule approximation. It depends on the fourth derivative of the function and the width of the subintervals, helping assess the accuracy of the numerical method.
Video consigliato:
07:01
Intro to the Chain Rule Example 1
Pratica correlata
Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

b. Evaluate the integral directly and find |ES|.

∫ from 0 to π of sin(t) dt

38
views
Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

b. Evaluate the integral directly and find |ES|.

∫ from 1 to 2 of 1 / s² ds

22
views
Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

b. Evaluate the integral directly and find |ES|.

∫ from -2 to 0 of (x² - 1) dx

22
views
Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

b. Evaluate the integral directly and find |ES|.

∫ from 1 to 2 of x dx

24
views
Domanda del libro di testo

The instructions for the integrals in Exercises 1–10 have three parts, one for the Midpoint Rule, one for the Trapezoidal Rule, and one for Simpson’s Rule.

III. Using Simpson's Rule

a. Estimate the integral with n = 4 steps and find an upper bound for |ES|.

∫ from 0 to 2 of (t³ + t) dt

26
views