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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 30a

Exercises 27–40 contain linear equations with constants in denominators. Solve each equation. x/5 - 1/2 = x/6

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Step 1: Identify the least common denominator (LCD) of all the denominators in the equation. The denominators are 5, 2, and 6. The LCD is 30.
Step 2: Multiply every term in the equation by the LCD (30) to eliminate the fractions. This gives: 30 * (x/5) - 30 * (1/2) = 30 * (x/6).
Step 3: Simplify each term after multiplying by the LCD. For example, 30 * (x/5) becomes 6x, 30 * (1/2) becomes 15, and 30 * (x/6) becomes 5x. The equation now reads: 6x - 15 = 5x.
Step 4: Isolate the variable x by subtracting 5x from both sides of the equation. This simplifies to: 6x - 5x - 15 = 0, which further simplifies to: x - 15 = 0.
Step 5: Solve for x by adding 15 to both sides of the equation. This gives: x = 15.

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