In Exercises 29–36, simplify and write the result in standard form. √(12 - 4 × 0.5 × 5)
Ch. 1 - Equations and Inequalities

Capitolo 2, Problema 37
In Exercises 35–54, solve each formula for the specified variable. Do you recognize the formula? If so, what does it describe? A = (1/2)bh for b
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Identify the formula given: \(A = \frac{1}{2}bh\). This is the formula for the area of a triangle, where \(A\) is the area, \(b\) is the base, and \(h\) is the height.
The problem asks to solve the formula for the variable \(b\), which means we want to isolate \(b\) on one side of the equation.
Start by eliminating the fraction. Multiply both sides of the equation by 2 to get rid of the denominator: \$2A = bh$.
Next, to isolate \(b\), divide both sides of the equation by \(h\): \(b = \frac{2A}{h}\).
Now the formula is solved for \(b\), expressing the base of the triangle in terms of the area and height.

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Solving Formulas for a Variable
This involves isolating the specified variable on one side of the equation. It requires using algebraic operations such as multiplication, division, addition, or subtraction to rewrite the formula in terms of the desired variable.
Video consigliato:
Solving Quadratic Equations Using The Quadratic Formula
Area of a Triangle Formula
The formula A = (1/2)bh calculates the area of a triangle, where 'b' is the base length and 'h' is the height. Understanding this geometric context helps interpret the variables and the meaning of the formula.
Video consigliato:
Solving Quadratic Equations Using The Quadratic Formula
Algebraic Manipulation Techniques
These techniques include multiplying both sides by a common denominator or dividing both sides by a coefficient to isolate variables. Mastery of these methods is essential for rearranging formulas accurately.
Video consigliato:
Introduction to Algebraic Expressions
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