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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 47

Perform the indicated operations and write the result in standard form. −6−−1248\(\frac{-6 - \sqrt{-12}\)}{48}

Guida verificata passo dopo passo
1
Identify the expression to simplify: \(\frac{-6 - \sqrt{-12}}{48}\).
Recognize that the square root of a negative number involves imaginary numbers. Rewrite \(\sqrt{-12}\) as \(\sqrt{12} \times \sqrt{-1}\), which is \(\sqrt{12}i\).
Simplify \(\sqrt{12}\) by factoring it into \(\sqrt{4 \times 3}\), which equals \(2\sqrt{3}\). So, \(\sqrt{-12} = 2\sqrt{3}i\).
Substitute back into the original expression: \(\frac{-6 - 2\sqrt{3}i}{48}\).
Separate the real and imaginary parts by dividing both terms in the numerator by 48: \(\frac{-6}{48} - \frac{2\sqrt{3}i}{48}\). Then simplify each fraction to write the expression in standard form $a + bi$.

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