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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
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Capitolo 2, Problema 65

In Exercises 59–94, solve each absolute value inequality. |2(x - 1) + 4| ≤ 8

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Start by rewriting the absolute value inequality \( |2(x - 1) + 4| \leq 8 \) as a compound inequality without the absolute value: \( -8 \leq 2(x - 1) + 4 \leq 8 \).
Next, simplify the expression inside the inequality by distributing and combining like terms: \( 2(x - 1) + 4 = 2x - 2 + 4 = 2x + 2 \). So the inequality becomes \( -8 \leq 2x + 2 \leq 8 \).
Now, isolate the term with \( x \) by subtracting 2 from all parts of the inequality: \( -8 - 2 \leq 2x + 2 - 2 \leq 8 - 2 \), which simplifies to \( -10 \leq 2x \leq 6 \).
Then, solve for \( x \) by dividing all parts of the inequality by 2 (remember to keep the inequality signs the same since 2 is positive): \( \frac{-10}{2} \leq \frac{2x}{2} \leq \frac{6}{2} \), resulting in \( -5 \leq x \leq 3 \).
Finally, write the solution set as all \( x \) values between \( -5 \) and \( 3 \), inclusive, which can be expressed in interval notation as \( [-5, 3] \).

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Absolute Value Inequalities

An absolute value inequality involves expressions within absolute value bars and compares them to a number. To solve |A| ≤ B, where B ≥ 0, rewrite it as a compound inequality: -B ≤ A ≤ B. This approach helps find the range of values for the variable that satisfy the inequality.
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Distributive Property

The distributive property allows you to multiply a single term across terms inside parentheses: a(b + c) = ab + ac. Applying this property simplifies expressions like 2(x - 1) into 2x - 2, making it easier to isolate variables and solve inequalities.
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Solving Linear Inequalities

Solving linear inequalities involves isolating the variable on one side using inverse operations while maintaining inequality direction. When multiplying or dividing by a negative number, the inequality sign reverses. This process helps determine the solution set for the variable.
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