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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 18

Solve each equation in Exercises 15–34 by the square root property. 3x2 - 1 = 47

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1
Start by isolating the quadratic term. Add 1 to both sides of the equation to eliminate the constant term on the left-hand side: 3x^2 = 47 + 1.
Simplify the right-hand side to combine the constants: 3x^2 = 48.
Divide both sides of the equation by 3 to isolate x^2: x^2 = \(\frac{48}{3}\).
Simplify the fraction on the right-hand side: x^2 = 16.
Apply the square root property to solve for x. Remember to include both the positive and negative roots: x = \(\pm\) \(\sqrt{16}\).

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Square Root Property

The square root property states that if an equation is in the form of x^2 = k, then the solutions for x can be found by taking the square root of both sides, resulting in x = ±√k. This property is essential for solving quadratic equations where the variable is squared.
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