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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 67

Solve each equation by completing the square. 3x2−12x+11=03x^2 -12x+11= 0

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Start with the given quadratic equation: \(3x^2 - 12x + 11 = 0\).
Divide the entire equation by 3 to make the coefficient of \(x^2\) equal to 1: \(x^2 - 4x + \frac{11}{3} = 0\).
Isolate the constant term on one side: \(x^2 - 4x = -\frac{11}{3}\).
To complete the square, take half of the coefficient of \(x\) (which is \(-4\)), square it, and add it to both sides. Half of \(-4\) is \(-2\), and \((-2)^2 = 4\). So add 4 to both sides: \(x^2 - 4x + 4 = -\frac{11}{3} + 4\).
Rewrite the left side as a perfect square: \((x - 2)^2 = -\frac{11}{3} + \frac{12}{3}\), then simplify the right side.

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