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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 106

Solve each equation in Exercises 83–108 by the method of your choice. 1/x + 1/(x + 3) = 1/4

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1
Identify the equation: \(\frac{1}{x} + \frac{1}{x + 3} = \frac{1}{4}\).
Find the least common denominator (LCD) for the fractions, which is \(4x(x + 3)\).
Multiply both sides of the equation by the LCD to eliminate the denominators: \(4x(x + 3) \times \left( \frac{1}{x} + \frac{1}{x + 3} \right) = 4x(x + 3) \times \frac{1}{4}\).
Simplify each term after multiplication: \(4(x + 3) + 4x = x(x + 3)\).
Rewrite the equation and expand all terms to form a quadratic equation: \(4x + 12 + 4x = x^2 + 3x\), then combine like terms and set the equation to zero.

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