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Solve and check: (x-1)/5 - (x+3)/2 = 1- x/4
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Ch. 2 - Functions and Graphs
Blitzer8th EditionCollege AlgebraISBN: 9780136970514
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TOC.tableOfContents
- Ch. P - Fundamental Concepts of Algebra311
- Ch. 1 - Equations and Inequalities398
- Ch. 2 - Functions and Graphs407
- Ch. 3 - Polynomial and Rational Functions306
- Ch. 4 - Exponential and Logarithmic Functions247
- Ch. 5 - Systems of Equations and Inequalities173
- Ch. 6 - Matrices and Determinants143
- Ch. 7 - Conic Sections124
- Ch. 8 - Sequences, Induction, and Probability251
Capitolo 3, Problema 124
Exercises 123–125 will help you prepare for the material covered in the next section. Solve for y : x = 5/y + 4
Guida verificata passo dopo passo1
Start by isolating the term containing y. Subtract 4 from both sides of the equation to get: x - 4 = 5/y.
To eliminate the fraction, multiply both sides of the equation by y. This gives: y(x - 4) = 5.
Next, divide both sides of the equation by (x - 4) to isolate y. This results in: y = 5 / (x - 4).
Ensure that the denominator (x - 4) is not equal to zero, as division by zero is undefined. Check the condition: x ≠ 4.
The solution for y is expressed as y = 5 / (x - 4), with the restriction that x ≠ 4.
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Solving Equations
Solving equations involves finding the value of a variable that makes the equation true. In this case, we need to isolate 'y' in the equation x = 5/y + 4. This process often requires algebraic manipulation, such as moving terms from one side of the equation to the other and performing operations like multiplication or division.
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5:02
Solving Logarithmic Equations
Rational Expressions
A rational expression is a fraction where the numerator and/or denominator are polynomials. In the equation given, 5/y is a rational expression. Understanding how to manipulate rational expressions, including finding a common denominator and simplifying, is crucial for solving equations that involve them.
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02:58Rationalizing Denominators
Inverse Operations
Inverse operations are pairs of operations that undo each other, such as addition and subtraction or multiplication and division. To solve for 'y', we will use inverse operations to isolate 'y' on one side of the equation. Recognizing which operations to apply is essential for effectively solving algebraic equations.
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8:38Performing Row Operations on Matrices
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