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Ch. 2 - Functions and Graphs
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 59

Let f(x) = 2x - 5 g(x) = 4x - 1 h(x) = x² + x + 2. Evaluate the indicated function without finding an equation for the function. (fog) (0)

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Identify the functions involved: \(f(x) = 2x - 5\) and \(g(x) = 4x - 1\). The problem asks for \((f \circ g)(0)\), which means \(f(g(0))\).
First, evaluate the inner function \(g(0)\) by substituting \(x = 0\) into \(g(x) = 4x - 1\). This gives \(g(0) = 4(0) - 1\).
Simplify the expression for \(g(0)\) to find its value.
Next, take the result from \(g(0)\) and substitute it into the outer function \(f(x) = 2x - 5\). So, compute \(f(g(0)) = 2 \times g(0) - 5\).
Simplify the expression for \(f(g(0))\) to find the final value of \((f \circ g)(0)\).

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