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Ch. 3 - Polynomial and Rational Functions
Blitzer - College Algebra 8th Edition
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Tutti i libri di testoBlitzer 8th EditionCh. 3 - Polynomial and Rational FunctionsProblema 55
Capitolo 4, Problema 55

Use transformations of f(x)=1/x or f(x)=1/x2 to graph each rational function. h(x)=1/(x−3)2+1

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1
Identify the base function given, which is \(f(x) = \frac{1}{x^2}\). This is the starting point for the transformations.
Recognize the horizontal shift in the function \(h(x) = \frac{1}{(x-3)^2} + 1\). The term \((x-3)\) inside the denominator indicates a shift to the right by 3 units.
Understand the vertical shift: the \(+1\) outside the fraction means the entire graph of \(\frac{1}{(x-3)^2}\) is shifted upward by 1 unit.
Combine the transformations: start with the graph of \(f(x) = \frac{1}{x^2}\), shift it right by 3 units to get \(\frac{1}{(x-3)^2}\), then shift it up by 1 unit to get \(h(x) = \frac{1}{(x-3)^2} + 1\).
Analyze the asymptotes: the vertical asymptote moves from \(x=0\) to \(x=3\) due to the horizontal shift, and the horizontal asymptote moves from \(y=0\) to \(y=1\) due to the vertical shift.

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Parent Rational Functions

Parent rational functions like f(x) = 1/x and f(x) = 1/x² serve as the basic models for more complex rational functions. Understanding their graphs, including asymptotes and general shape, is essential before applying transformations. For example, f(x) = 1/x has vertical and horizontal asymptotes at x=0 and y=0, respectively.
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Intro to Rational Functions

Transformations of Functions

Transformations include shifts, stretches, compressions, and reflections applied to the parent function's graph. Horizontal shifts move the graph left or right, vertical shifts move it up or down, and changes inside the function's formula affect these shifts. For h(x) = 1/(x−3)² + 1, the graph shifts right by 3 units and up by 1 unit.
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Domain & Range of Transformed Functions

Asymptotes of Rational Functions

Asymptotes are lines that the graph approaches but never touches. Vertical asymptotes occur where the denominator is zero, indicating undefined points, while horizontal asymptotes describe end behavior as x approaches infinity. For h(x) = 1/(x−3)² + 1, the vertical asymptote is x=3 and the horizontal asymptote is y=1.
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Introduction to Asymptotes
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