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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 17

In Exercises 1–18, solve each system by the substitution method. {x+y=1(x−1)2+(y+2)2=10\(\begin{cases}\) x + y = 1 \\ (x - 1)^2 + (y + 2)^2 = 10 \(\end{cases}\)

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Start with the given system of equations: \(x + y = 1\) and \((x - 1)^2 + (y + 2)^2 = 10\).
From the first equation, solve for one variable in terms of the other. For example, express \(y\) as \(y = 1 - x\).
Substitute the expression for \(y\) into the second equation to replace \(y\) with \(1 - x\). This gives: \((x - 1)^2 + ((1 - x) + 2)^2 = 10\).
Simplify the equation by expanding the squares and combining like terms to form a quadratic equation in terms of \(x\).
Solve the quadratic equation for \(x\), then substitute each solution back into \(y = 1 - x\) to find the corresponding \(y\) values.

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