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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 6, Problema 25

In Exercises 19–28, solve each system by the addition method. {x2+y2=25(x−8)2+y2=41\(\begin{cases}\) x^2 + y^2 = 25 \\ (x - 8)^2 + y^2 = 41 \(\end{cases}\)

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Identify the system of equations: \(x^2 + y^2 = 25\) and \((x - 8)^2 + y^2 = 41\).
Expand the second equation: \((x - 8)^2 + y^2 = x^2 - 16x + 64 + y^2 = 41\).
Rewrite the expanded second equation as \(x^2 - 16x + 64 + y^2 = 41\).
Subtract the first equation \(x^2 + y^2 = 25\) from the expanded second equation to eliminate \(y^2\) and \(x^2\): \((x^2 - 16x + 64 + y^2) - (x^2 + y^2) = 41 - 25\).
Simplify the resulting equation to isolate \(x\) and solve for its value(s).

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