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Ch. 6 - Matrices and Determinants
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 19

Let A=[−3−72−950]A = \(\begin{bmatrix}\) -3 & -7 \\ 2 & -9 \\ 5 & 0 \(\end{bmatrix}\) and B=[−5−1003−4]B = \(\begin{bmatrix}\) -5 & -1 \\ 0 & 0 \\ 3 & -4 \(\end{bmatrix}\). Solve each matrix equation for X. 2X + A = B

Guida verificata passo dopo passo
1
Identify the given matrices and the equation to solve: \(2X + A = B\), where \(A = \begin{bmatrix} -3 & -7 \\ 2 & -9 \\ 5 & 0 \end{bmatrix}\) and \(B = \begin{bmatrix} -5 & -1 \\ 0 & 0 \\ 3 & -4 \end{bmatrix}\).
Isolate the term with \(X\) by subtracting matrix \(A\) from both sides of the equation: \(2X = B - A\).
Perform the matrix subtraction \(B - A\) by subtracting corresponding elements of \(A\) from \(B\): \(\left(b_{ij} - a_{ij}\right)\) for each element.
Divide each element of the resulting matrix \$2X$ by 2 to solve for $X$: \(X = \frac{1}{2}(B - A)\).
Write the final expression for \(X\) as \(X = \frac{1}{2} \left( B - A \right)\), which represents the solution matrix.

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