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Ch. 6 - Matrices and Determinants
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 29

Solve each system of equations using matrices. Use Gaussian elimination with back-substitution or Gauss-Jordan elimination.
{x+2y=z−1x=4+y−zx+y−3z=−2\(\begin{cases}\) x + 2y = z - 1 \\ x = 4 + y - z \\ x + y - 3z = -2 \(\end{cases}\)

Guida verificata passo dopo passo
1
Step 1: Write the system of equations in standard form, aligning variables on the left and constants on the right: \(x + 2y - z = -1\) \(x - y + z = 4\) \(x + y - 3z = -2\)
Step 2: Set up the augmented matrix representing the system: \[\left[\begin{array}{ccc|c} 1 & 2 & -1 & -1 \\ 1 & -1 & 1 & 4 \\ 1 & 1 & -3 & -2 \end{array}\right]\]
Step 3: Use Gaussian elimination to create zeros below the leading 1 in the first column. For example, subtract the first row from the second and third rows: Row2 = Row2 - Row1 Row3 = Row3 - Row1
Step 4: Continue the elimination process to get the matrix into upper triangular form, then use back-substitution to solve for variables starting from the last row upwards.
Step 5: Alternatively, perform Gauss-Jordan elimination by continuing row operations to get the matrix into reduced row echelon form, where the left side is the identity matrix, and the right side gives the solution directly.

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