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Ch. 8 - Sequences, Induction, and Probability
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 86

Solve: 6∣1–2x∣—7=116|1 – 2x| — 7 = 11.

Guida verificata passo dopo passo
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Start by isolating the absolute value expression. Add 7 to both sides of the equation: 6|1 – 2x| – 7 + 7 = 11 + 7, which simplifies to 6|1 – 2x| = 18.
Next, divide both sides of the equation by 6 to solve for the absolute value: |1 – 2x| = 18 / 6, which simplifies to |1 – 2x| = 3.
Recall that the absolute value equation |A| = B means A = B or A = -B. So, set up two separate equations: 1 – 2x = 3 and 1 – 2x = -3.
Solve each equation for x separately. For 1 – 2x = 3, subtract 1 from both sides and then divide by -2. For 1 – 2x = -3, subtract 1 from both sides and then divide by -2.
Write the two solutions for x obtained from the previous step. These are the values of x that satisfy the original equation.

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