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Ch. 8 - Sequences, Induction, and Probability
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 103

Solve: x/(x−3)=2x/(x−3)−5/3

Guida verificata passo dopo passo
1
Start by observing the equation: \(\frac{x}{x-3} = \frac{2x}{x-3} - \frac{5}{3}\). Notice that the denominators on the left and right sides involve \(x-3\), so we should consider the domain restriction \(x \neq 3\) to avoid division by zero.
To eliminate the denominators, multiply both sides of the equation by the least common denominator (LCD). The denominators are \(x-3\) and 3, so the LCD is \(3(x-3)\). Multiply every term by \(3(x-3)\):
\[3(x-3) \cdot \frac{x}{x-3} = 3(x-3) \cdot \frac{2x}{x-3} - 3(x-3) \cdot \frac{5}{3}\]
Simplify each term by canceling the denominators:
\[3x = 3 \cdot 2x - 5(x-3)\]
Now, expand and simplify the right side:
\[3x = 6x - 5x + 15\]
Combine like terms on the right side:
\[3x = (6x - 5x) + 15 = x + 15\]
Finally, isolate \(x\) by subtracting \(x\) from both sides:
\[3x - x = 15\]
Simplify the left side:
\[2x = 15\]
At this point, you can solve for \(x\) by dividing both sides by 2.

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