Factor completely, or state that the polynomial is prime. 64-x^2

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Recognize that the given polynomial, 64 - x^2, is a difference of squares. The general formula for factoring a difference of squares is a^2 - b^2 = (a - b)(a + b).

Identify the terms in the polynomial that correspond to a^2 and b^2. Here, 64 is a perfect square (8^2), and x^2 is also a perfect square.

Rewrite the polynomial in the form of a^2 - b^2. In this case, it becomes (8)^2 - (x)^2.

Apply the difference of squares formula: (a - b)(a + b). Substitute a = 8 and b = x into the formula to get (8 - x)(8 + x).

Verify that the factorization is correct by expanding (8 - x)(8 + x) to ensure it simplifies back to 64 - x^2.

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Factoring Polynomials

Factoring polynomials involves expressing a polynomial as a product of its simpler components, or factors. This process is essential for simplifying expressions and solving equations. Common techniques include identifying common factors, using special products, and applying methods like grouping or the quadratic formula when applicable.

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Difference of Squares

The difference of squares is a specific factoring pattern that applies to expressions in the form of a^2 - b^2. It can be factored into (a - b)(a + b). Recognizing this pattern is crucial for quickly factoring polynomials like 64 - x^2, where 64 is 8^2 and x^2 is x^2, allowing for efficient simplification.

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Prime Polynomials

A polynomial is considered prime if it cannot be factored into the product of two non-constant polynomials with real coefficients. Understanding the criteria for prime polynomials is important for determining whether a polynomial can be simplified further or if it stands alone as an irreducible expression.

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Pratica correlata

Domanda del libro di testo

Perform the indicated computations. Write the answers in scientific notation. If necessary, round the decimal factor in your scientific notation answer to two decimal places. $(6.1 \times 10^{- 8}) (2 \times 10^{- 4})$