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Ch. P - Fundamental Concepts of Algebra
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 39

In Exercises 15–58, find each product. (1−y5)(1+y5)

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1
Recognize that the given expression (1−y^5)(1+y^5) is a product of two binomials in the form (a−b)(a+b). This is a difference of squares formula.
Recall the difference of squares formula: (a−b)(a+b) = a^2 − b^2. Here, a = 1 and b = y^5.
Substitute the values of a and b into the formula: a^2 − b^2 becomes 1^2 − (y^5)^2.
Simplify each term: 1^2 simplifies to 1, and (y^5)^2 simplifies to y^(5×2) = y^10.
Combine the simplified terms to get the final expression: 1 − y^10.

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Difference of Squares

The difference of squares is a fundamental algebraic identity that states that for any two terms a and b, the expression (a - b)(a + b) equals a² - b². This identity is crucial for simplifying expressions that are structured as a product of a sum and a difference, allowing for easier calculations and factorizations.
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