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Ch. P - Fundamental Concepts of Algebra
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 47

Add or subtract as indicated. 2/5x − (x+1)/4x

Guida verificata passo dopo passo
1
Identify the expression to simplify: \(\frac{2}{5x} - \frac{x+1}{4x}\).
Find the least common denominator (LCD) of the two fractions. Since the denominators are \$5x$ and \$4x$, the LCD is \$20x$.
Rewrite each fraction with the common denominator \$20x$: multiply numerator and denominator of \(\frac{2}{5x}\) by 4, and multiply numerator and denominator of \(\frac{x+1}{4x}\) by 5.
Express the subtraction with the common denominator: \(\frac{2 \times 4}{20x} - \frac{(x+1) \times 5}{20x}\), which simplifies to \(\frac{8}{20x} - \frac{5(x+1)}{20x}\).
Combine the numerators over the common denominator: \(\frac{8 - 5(x+1)}{20x}\), then simplify the numerator by distributing and combining like terms.

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