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Ch. P - Fundamental Concepts of Algebra
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 53

In Exercises 33–68, add or subtract as indicated. 3/(x+1) − 3/x

Guida verificata passo dopo passo
1
Identify the two rational expressions to be subtracted: \(\frac{3}{x+1} - \frac{3}{x}\).
Find the least common denominator (LCD) of the two fractions. Since the denominators are \(x+1\) and \(x\), the LCD is \(x(x+1)\).
Rewrite each fraction with the LCD as the new denominator by multiplying numerator and denominator appropriately: \(\frac{3}{x+1} = \frac{3x}{x(x+1)}\) and \(\frac{3}{x} = \frac{3(x+1)}{x(x+1)}\).
Subtract the numerators over the common denominator: \(\frac{3x}{x(x+1)} - \frac{3(x+1)}{x(x+1)} = \frac{3x - 3(x+1)}{x(x+1)}\).
Simplify the numerator by distributing and combining like terms: \(3x - 3(x+1) = 3x - 3x - 3 = -3\), so the expression becomes \(\frac{-3}{x(x+1)}\).

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