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Ch. P - Fundamental Concepts of Algebra
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 83

In Exercises 83–90, perform the indicated operation or operations. (3x+4y)2−(3x−4y)2

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1
Recognize that the given expression involves the difference of two squares: \((3x + 4y)^2 - (3x - 4y)^2\). The difference of squares formula is \(a^2 - b^2 = (a - b)(a + b)\).
Identify \(a = (3x + 4y)\) and \(b = (3x - 4y)\) in the expression. Substitute these into the difference of squares formula.
Apply the formula: \((3x + 4y) - (3x - 4y)\) and \((3x + 4y) + (3x - 4y)\). Simplify each term inside the parentheses.
Simplify \((3x + 4y) - (3x - 4y)\) to \(8y\) and \((3x + 4y) + (3x - 4y)\) to \(6x\).
Multiply the simplified terms: \(8y \cdot 6x\). This gives the final simplified expression, which you can calculate if needed.

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