give-the-balanced-equation-for-the-following-half-reactions-occurring-in-an-acid

Question

Give the balanced equation for the following half-reactions occurring in an acidic solution.
i. I₂(s) → I⁻(aq)
ii. Cu⁺(aq) → Cu(s)
iii. MnO₄⁻(aq) → Mn²⁺(aq)
iv. PbO₂(s) → Pb²⁺(aq)

Accepted Answer

i. I_{2}(s) + 2 $$e^{−}$$ → 2 $$I^{−}(aq) ii$$. $$Cu^{+}(aq$$) + $$e^{−}$$ → Cu(s) iii. MnO_{4}^{−}(aq) + 8 $$H^{+}(aq) + 5$$ $$e^{−}$$ → $$Mn^{2+}(aq) + 4$$ $$H_{2}O(l) iv. $$PbO_{2}(s) + 4 $$H^{+}(aq) + 2$$ $$e^{−}$$ → $$Pb^{2+}(aq) + 2H$$_{2}O(l)

Answer

i. I_{2}(s) + 2 $$e^{−}$$ → 2 $$I^{−}(aq) ii$$. $$Cu^{+}(aq$$) + $$e^{−}$$ → Cu(s)   iii. MnO_{4}^{−}(aq) + 8 $$H^{+}(aq$$) → $$Mn^{2+}(aq) + 4$$ $$H_{2}O(l) + 5$$ $$e^{−} iv. $$PbO_{2}(s) + 4 $$H^{+}(aq$$) → $$Pb^{2+}(aq) + 2H$$_{2}O(l) + 2 $$e^{−}$$

Answer

i. I_{2}(s) → 2 $$I^{−}(aq) + 2$$ $$e^{−} ii$$. $$Cu^{+}(aq$$) → Cu(s) + $$e^{−}$$ iii. MnO_{4}^{−}(aq) + 8 $$H^{+}(aq$$) → $$Mn^{2+}(aq) + 4$$ $$H_{2}O(l) + 5$$ $$e^{−} iv. $$PbO_{2}(s) + 4 $$H^{+}(aq$$) → $$Pb^{2+}(aq) + 2H$$_{2}O(l) + 2 $$e^{−}$$

Answer

i. I_{2}(s) → 2 $$I^{−}(aq) + 2$$ $$e^{−} ii$$. $$Cu^{+}(aq$$) → Cu(s) + $$e^{−}$$ iii. MnO_{4}^{−}(aq) + 8 $$H^{+}(aq) + 5$$ $$e^{−}$$ → $$Mn^{2+}(aq) + 4$$ $$H_{2}O(l) iv. $$PbO_{2}(s) + 4 $$H^{+}(aq) + 2$$ $$e^{−}$$ → $$Pb^{2+}(aq) + 2H$$_{2}O(l)

Give the balanced equation for the following half-reactions occurring in an acidic solution.i. I2(s) → I−(aq)ii. Cu+(aq) → Cu(s)iii. MnO4−(aq) → Mn2+(aq)iv. PbO2(s) → Pb2+(aq)

Give the balanced equation for the following half-reactions occurring in an acidic solution.
i. I₂(s) → I⁻(aq)
ii. Cu⁺(aq) → Cu(s)
iii. MnO₄⁻(aq) → Mn²⁺(aq)
iv. PbO₂(s) → Pb²⁺(aq)