what-is-the-balanced-nuclear-equation-when-the-isotope-225ac-decays-by-alpha-emi

Question

What is the balanced nuclear equation when the isotope actinium-225 decays by alpha emission?

Accepted Answer

^{225}_{89}Ac → ^{221}_{87}Fr $$+ ^{4}$$_{2}He

Answer

^{225}_{89}Ac $$+ ^{4}$$_{2}He → ^{229}_{91}Fr

Answer

^{225}_{89}Ac → ^{229}_{91}Pa $$+ ^{4}$$_{2}He

Answer

^{225}_{89}Ac $$+ ^{4}$$_{2}He → ^{221}_{87}Ac