determine-the-equilibrium-constant-for-the-reaction-with-their-ksp-and-kf-values

Question

Determine the equilibrium constant for the reaction given K_sp and K_f values.
CuS (s) + 4 CN^- (aq) ⇌ Cu(CN)₄^2- (aq) + S^2- (aq)
K_sp (CuS) = 2 × 10^-47, K_f (Cu(CN)₄^2-) = 1 × 10²⁵

Accepted Answer

2 × $$10^{-22}$$

Answer

5 × $$10^{71}$$

Answer

2 × $$10^{-47}$$

Answer

1 × $$10^{25}$$