a-certain-voltaic-cell-has-a-cell-potential-of-1-60-v-works-on-an-overall-reacti

Question

A certain voltaic cell has a cell potential of +1.60 V works on an overall reaction of AuBr_{4}^{–}(aq) + Cr(s) → Au(s) + 4 $$Br^{–}(aq$$) + $$Cr^{3+}(aq). $$Provide the two half-cell reactions involved.

Accepted Answer

Oxidation half-reaction: Cr(s) → $$Cr^{3+}(aq) + 3$$ $$e^{–}$$ Reduction half-reaction: AuBr_{4}^{–}(aq) + 3 $$e^{–}$$ → Au(s) + 4 $$Br^{–}(aq)$$

Answer

Oxidation half-reaction: Cr(s) + 3 $$e^{–}$$ → $$Cr^{3+}(aq) $$Reduction half-reaction: AuBr_{4}^{–}(aq) + 3 $$e^{–}$$ → Au(s) + 4 $$Br^{–}(aq)$$

Answer

Oxidation half-reaction: AuBr_{4}^{–}(aq) → Au(s) + 4 $$Br^{–}(aq) + 3$$ $$e^{–}$$ Reduction half-reaction: Cr(s) → $$Cr^{3+}(aq) + 3$$ $$e^{–}$$

Answer

Oxidation half-reaction: AuBr_{4}^{–}(aq) + 3 $$e^{–}$$ → Au(s) + 4 $$Br^{–}(aq) $$Reduction half-reaction: Cr(s) + 3 $$e^{–}$$ → $$Cr^{3+}(aq)$$

A certain voltaic cell has a cell potential of +1.60 V works on an overall reaction of AuBr4–(aq) + Cr(s) → Au(s) + 4 Br–(aq) + Cr3+(aq). Provide the two half-cell reactions involved.

A certain voltaic cell has a cell potential of +1.60 V works on an overall reaction of AuBr₄^–(aq) + Cr(s) → Au(s) + 4 Br^–(aq) + Cr³⁺(aq). Provide the two half-cell reactions involved.