the-reaction-ph3bcl3-s-ph3-g-bcl3-g-has-kc-6-96-x-10-5-at-60-c-determine-the-val

Question

The reaction $$PH_{3}$$BCl_{3}(s) ⇌ PH_{3}(g) + BCl_{3}(g) has K_{c} = 6.96 × $$10^{–5} at 60$$ ºC. Determine the value of K_{p}.

Accepted Answer

0.052

Answer

0.931

Answer

2.349

Answer

10.033

The reaction PH3BCl3(s) ⇌ PH3(g) + BCl3(g) has Kc = 6.96 × 10–5 at 60 ºC. Determine the value of Kp.