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Ch.10 - Gases
Brown - Chemistry: The Central Science 14th Edition
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232Non è quello che usi tu?Cambia libro di testo
Capitolo 10, Problema 87

Arsenic(III) sulfide sublimes readily, even below its melting point of 320 °C. The molecules of the vapor phase are found to effuse through a tiny hole at 0.52 times the rate of effusion of Xe atoms under the same conditions of temperature and pressure. What is the molecular formula of arsenic(III) sulfide in the gas phase?

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Use Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass: \( \frac{\text{Rate}_1}{\text{Rate}_2} = \sqrt{\frac{M_2}{M_1}} \).
Identify the given rates of effusion: the rate of effusion of arsenic(III) sulfide is 0.52 times that of xenon (Xe).
Set up the equation using Graham's law: \( 0.52 = \sqrt{\frac{M_{\text{Xe}}}{M_{\text{As}_x\text{S}_y}}} \), where \( M_{\text{Xe}} \) is the molar mass of xenon.
Square both sides of the equation to solve for the molar mass of arsenic(III) sulfide: \( 0.52^2 = \frac{M_{\text{Xe}}}{M_{\text{As}_x\text{S}_y}} \).
Calculate the molar mass of arsenic(III) sulfide using the known molar mass of xenon (131.29 g/mol) and determine the molecular formula by comparing the calculated molar mass to possible combinations of arsenic and sulfur atoms.

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Effusion and Graham's Law

Effusion is the process by which gas molecules escape through a tiny hole into a vacuum. Graham's Law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. This means that lighter gases effuse faster than heavier gases, allowing us to compare the effusion rates of different substances to deduce their molar masses.
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Graham's Law of Effusion

Molecular Formula

The molecular formula of a compound indicates the number and type of atoms present in a molecule. For arsenic(III) sulfide, the formula can be derived from the stoichiometry of the elements involved. Understanding how to determine the molecular formula from empirical data, such as effusion rates, is crucial for identifying the compound in question.
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Determining Molecular Formulas

Molar Mass Calculation

To find the molecular formula of arsenic(III) sulfide, we need to calculate its molar mass based on the effusion rate compared to xenon (Xe). By using the known molar mass of xenon and the ratio of effusion rates, we can derive the molar mass of arsenic(III) sulfide, which will help us confirm its molecular formula in the gas phase.
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Molar Mass Calculation Example
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A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 105 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 31 s for 1.0 L of O2 gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; in other words, rate is the amount that diffuses over the time it takes to diffuse.)

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