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Ch.20 - Electrochemistry
Brown - Chemistry: The Central Science 14th Edition
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232Non è quello che usi tu?Cambia libro di testo
Capitolo 20, Problema 91b

(b) What amperage is required to plate out 0.250 mol Cr from a Cr3+ solution in a period of 8.00 h?

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1
Identify the relevant electrochemical reaction: The reduction of Cr³⁺ to Cr metal is represented by the half-reaction: Cr³⁺ + 3e⁻ → Cr.
Determine the total charge needed: Since 1 mole of Cr requires 3 moles of electrons, calculate the total moles of electrons needed for 0.250 mol of Cr using the stoichiometry of the reaction.
Convert moles of electrons to charge: Use Faraday's constant (approximately 96485 C/mol) to convert the moles of electrons to total charge in coulombs.
Calculate the current (amperage): Use the formula I = Q/t, where I is the current in amperes, Q is the total charge in coulombs, and t is the time in seconds. Convert the given time from hours to seconds.
Solve for the current: Substitute the values for Q and t into the formula to find the required current in amperes.

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