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Ch.4 - Reactions in Aqueous Solution
Brown - Chemistry: The Central Science 14th Edition
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Tutti i libri di testoBrown 14th EditionCh.4 - Reactions in Aqueous SolutionProblema 88b
Capitolo 4, Problema 88b

A solution is made by mixing 1.5 g of LiOH and 23.5 mL of 1.000 M HNO3. (b) Calculate the concentration of each ion remaining in solution.

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Determine the moles of LiOH using its molar mass: \( \text{moles of LiOH} = \frac{1.5 \text{ g}}{\text{molar mass of LiOH}} \).
Calculate the moles of HNO3 using its concentration and volume: \( \text{moles of HNO3} = 1.000 \text{ M} \times 0.0235 \text{ L} \).
Write the balanced chemical equation for the reaction: \( \text{LiOH} + \text{HNO}_3 \rightarrow \text{LiNO}_3 + \text{H}_2\text{O} \).
Determine the limiting reactant by comparing the moles of LiOH and HNO3.
Calculate the moles of Li+ remaining in solution, considering the stoichiometry of the reaction and the limiting reactant.

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Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions. It involves using balanced chemical equations to determine the relationships between the amounts of substances consumed and produced. In this case, understanding the stoichiometric ratios between LiOH and HNO3 is essential to find out how much Li+ remains after the reaction.
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Stoichiometry Concept

Molarity

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is crucial for calculating the concentration of ions in a solution. In this question, the molarity of HNO3 is given, which will help determine how many moles of HNO3 are present and how they react with LiOH.
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Molarity

Neutralization Reaction

A neutralization reaction occurs when an acid reacts with a base to produce water and a salt. In this scenario, HNO3 (an acid) reacts with LiOH (a base) to form water and LiNO3. Understanding this concept is vital for determining the extent of the reaction and calculating the remaining concentration of Li+ in the solution.
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Lewis Dot Structures: Neutral Compounds
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