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Ch.5 - Thermochemistry
Brown - Chemistry: The Central Science 14th Edition
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232Non è quello che usi tu?Cambia libro di testo
Capitolo 5, Problema 63

Calculate the enthalpy change for the reaction P4O6(s) + 2 O2(g) → P4O10(s) given the following enthalpies of reaction: P4(s) + 3 O2(g) → P4O6(s) ΔH = -1640.1 kJ P4(s) + 5 O2(g) → P4O10(s) ΔH = -2940.1 kJ

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1
Identify the target reaction: P_4O_6(s) + 2 O_2(g) → P_4O_10(s).
Write the given reactions: 1) P_4(s) + 3 O_2(g) → P_4O_6(s) with ΔH = -1640.1 kJ, 2) P_4(s) + 5 O_2(g) → P_4O_10(s) with ΔH = -2940.1 kJ.
Reverse the first reaction to match the formation of P_4O_6(s) as a reactant: P_4O_6(s) → P_4(s) + 3 O_2(g), changing the sign of ΔH to +1640.1 kJ.
Add the reversed first reaction to the second reaction to cancel out P_4(s) and some O_2(g), resulting in the target reaction.
Calculate the enthalpy change for the target reaction by adding the ΔH values of the modified reactions: ΔH = (+1640.1 kJ) + (-2940.1 kJ).

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