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Ch.15 - Chemical Equilibrium
Brown - Chemistry: The Central Science 15th Edition
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970Non è quello che usi tu?Cambia libro di testo
Capitolo 15, Problema 67

Ozone, O3, decomposes to molecular oxygen in the stratosphere according to the reaction 2 O3(𝑔) ⟶ 3 O2(𝑔). Would increasing the pressure by decreasing the size of the reaction vessel favor the formation of ozone or of oxygen?

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Consider Le Chatelier's Principle, which states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change.
In the given reaction, 2 O_3(g) ⟶ 3 O_2(g), compare the number of moles of gas on each side of the equation.
The reactant side has 2 moles of O_3, while the product side has 3 moles of O_2.
Increasing the pressure by decreasing the volume of the reaction vessel will shift the equilibrium towards the side with fewer moles of gas to reduce the pressure.
Since the reactant side has fewer moles of gas (2 moles of O_3) compared to the product side (3 moles of O_2), the equilibrium will shift towards the formation of ozone, O_3.

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Le Chatelier's Principle

Le Chatelier's Principle states that if a dynamic equilibrium is disturbed by changing the conditions, the system will adjust to counteract the change and restore a new equilibrium. In the context of gas reactions, increasing pressure favors the side of the reaction with fewer moles of gas, as this reduces the overall pressure.
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Stoichiometry of the Reaction

The stoichiometry of a chemical reaction describes the quantitative relationship between the reactants and products. In the given reaction, 2 moles of ozone (O3) decompose to form 3 moles of oxygen (O2). This indicates that the product side has more moles of gas than the reactant side, which is crucial for understanding how changes in pressure will affect the reaction.
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Effect of Pressure on Gas Reactions

The effect of pressure on gas reactions is significant because gases occupy space and their behavior is influenced by changes in volume and pressure. According to the ideal gas law, increasing pressure by reducing the volume of the reaction vessel will shift the equilibrium towards the side with fewer gas molecules, which in this case is the reactants (ozone).
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